Nuprl Definition : fpf-val 0,22

z != f(x)  P(a;z) == x  dom(f)  P(x;f(x)) 
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clarification:

fpf-val(eq; f; x; a,z.P(a;z)) == fpf-dom(eq; x; f)  P(x;fpf-ap(f; eq; x)) 
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Definitionsf(x), x  dom(f), b, P  Q
FDL editor aliasesfpf-val

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